Question

A car goes from 30 m/s to 10 m/s how long does it take with a acceleration of -2

Answer 1

`\large \bf \implies{s = 200 \: m}`

Explanation:

Given :

• Initial velocity (u) = 30 m/s
• Final velocity (v) = 10 m/s
• Acceleration (a) = -2 m/s²

To Find :-

• Distance (s) = ?

Solution :-

Using third equation of motion we have find the distance :

• 2as = v² - u²

Putting the values according to equation :

• 2 × (-2) × s = (10)² - (30)²
• -4s = 100 - 900
• -4s = -800
• 
  `s = \frac{ \cancel{- 800}}{ \cancel{- 4}}`
• s = 200 m