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A car moving with an initial speed of 16 meters per second is brought to rest uniformly in 4. 0 seconds. How far does the car travel during this 4. 0-second interval?.

User Nyoka
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1 Answer

1 vote

Answer:

32 meters

Step-by-step explanation:

Use the formula for displacement

d = ut + (1/2)at²

where u = initial velocity , a is the acceleration and t is the time traveled

First let's find the acceleration given by (v - u)/t where v is the final velocity and t the time taken to reach this final velocity from initial velocity u

v = 0 , t = 4 secs, u = 16 m/s

a = (0 - 16)/4 = -16/4 = -4 m/s²

Plugging in values for u= 16 and a = -4 we get

So d = 16t + (1/2)(-4)t

= 16t -2t

Plugging in value for t = 4 gives us

= 16 x 4 - 2 x 4 x 4

= 64 - 32

= 32 meters