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26 votes
26 votes
Help please I need to find x and y

Help please I need to find x and y-example-1
User AyB
by
2.3k points

2 Answers

10 votes
10 votes
Hey, so I got
x = 5.9 units (just round it to 6)
y= 11.8 units (round it to 12)

Steps:

1) Use Soh Cah Toa to identify the unknown sides.

The side across the angle is the opposite. Therefore, the x side is opposite.
4√5 = 6.9 ( this side is the hypotenuse).
So we have the opposite side and the hypotenuse side. Therefore, we will use sine

2) Sin theta = opp/hyp
Sin 60 = opp/6.9

Multiply both sides by 6.9

6.9(sin60) = opp
5.9 = opp

3) now that you have side x, we will use x to figure out side y.

Identify the sides first. Side x is opposite and side y is the hypotenuse. Use sine to solve for side y

Sin theta = opp/hyp
Sin 30 = 5.9/hyp
0.5 = 5.9/hyp

Divide 0.5 and bring it over to the other side.

= 5.9/ hyp ÷ 0.5/1
= 5.9/hyp x 1/0.5
= 5.9/0.5
= 11.8 units (side Y)
Help please I need to find x and y-example-1
User Ronny Webers
by
2.3k points
13 votes
13 votes

Answer:


x=6\\y=12

Explanation:

To find the value of x you can use sin rule


sin(60)=(oppoaite)/(hypotenuse)\\(√(3) )/(2) =(x)/(4√(3) ) \\

Use cross multiplication


4*√(3) *√(3) =2x\\4*3=2x\\12=2x\\(12)/(2) =(2x)/(2) \\6 =x

To find the value of y you have to use sin rule again


sin(30)=(opposite)/(hypotenuse)\\(1)/(2) =(x)/(y) \\(1)/(2) =(6)/(y) \\

Use cross multiplication


y=6*2\\y=12

Hope this helps you.

Let me know if you have any other questions :-)

User Gary Carlyle Cook
by
3.0k points
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