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Mass X (2 kg) and mass Y (1 kg) are dropped from a tall building at the same time. After one second, X will be moving​
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Mass X (2 kg) and mass Y (1 kg) are dropped from a tall building at the same time. After one second, X will be moving​

User MarkDBlackwell
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1 Answer

1 vote

Answer:

See below

Step-by-step explanation:

Ignoring air friction...X will be moving the same speed as Y

vf = at

= 9.81 m/s^2 * 1 s = 9.81 m/s

User Tudor Luca
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