Question

1, 3/2 , 9/4 ... Find the 9th term

Answer 1

6561/256

Explanation:

You can notice that each term is equal to the previous term multiplied by 3/2. This means that it is a geometric series. The formula to find the nth term is as follows:

`a_(n)= a_(1) *(r)^(n-1)`

The first term, a1, is 1 and r, the common ratio is 3/2 because that is what you are multiplying by. We can also substitute in n as 9 because we are looking for the ninth term:

`a_(9) = 1 *((3)/(2) )^(9-1)\\\\a_(9) = ((3)/(2))^(8)\\\\a_(9) =(3^8)/(2^8) \\\\a_(9) =(6561)/(256)`