Question

(Cosec a -cot a)^2=1-cos\1+cos

Answer 1

Explanation:

`\displaystyle\\(cosec \alpha -cot\alpha )^2=\\\\((1)/(sin\alpha ) -(cos\alpha )/(sin\alpha ))^2 =\\\\((1-cos\alpha )/(sin\alpha ) )^2=\\\\((1-cos\alpha)^2 )/(sin^2\alpha )=\\\\ ((1-cos\alpha )^2)/(1-cos^2\alpha ) =\\\\((1-cos\alpha )^2)/((1+cos\alpha )(1-cos\alpha )) =\\\\(1-cos\alpha )/(1+cos\alpha )`