Question

Write the equation of the line that passes through the points (3,-2) and (-2,8).

Answer 1

`▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪`

Let's find the slope (m) of line passing through points (3 , -2) and (-2 , 8) :

• 
  `(y_2 - y_1)/(x_2 - x_1)`

• 
  `( - 2 - 8)/(3 - ( - 2))`

• 
  `( - 10)/(5)`

• 
  `- 2`

slope (m) = -2

now, let's plug the value of slope (m) and coordinates of point (3 , -2) to find c (y - intercept)

`y = mx + c`

• 
  `- 2 = (3 * - 2) + c`

• 
  `- 2 = - 6 + c`

• 
  `c = - 2 + 6`

• 
  `c = 4`

Y - intercept of the given line is 4, so the required equation will be :

• 
  `y = - 2x + 4`