Question

NO LINKS!! Please help me Part 1f​

Answer 1

I won’t bother putting on the same answer as the other person.

Explanation:

This is a linear sequence, as it has no indices in the nth term.

It starts with 3.

Thus, we only need to work out the 2nd term to have our answer.

3,4…

We know it will continue to be 3,4,5,6

There’s your answer

Answer 2

d) 3, 4, 5, 6

Explanation:

Given recursive rule:

`\begin{cases}a_n=2a_(n-1)-n\\a_1=3\end{cases}`

First four terms of the sequence:

`\implies a_1=3`

`\begin{aligned}\implies a_2 & =2a_((2-1))-2\\& = 2a_1-2\\& = 2(3)-2\\& = 6-2\\& = 4\end{aligned}`

`\begin{aligned}\implies a_3 & =2a_((3-1))-3\\& = 2a_2-3\\& = 2(4)-3\\& = 8-3\\& = 5\end{aligned}`

`\begin{aligned}\implies a_4 & =2a_((4-1))-4\\& = 2a_3-4\\& = 2(5)-4\\& = 10-4\\& = 6\end{aligned}`

Therefore, the first four terms of the sequence are 3, 4, 5, 6.