Question

Three integers have a mean of 8, a median of 8 and a range of 4.

Answer 1

Mean: average number
Median: middle number
Range: largest - smallest

Mean: ? + ? + ? = ? / 3 = 8, so 8x3=24, the equation is now ?+?+?=24

Median: ?,8,? Because median is 8

Range: 10,8,6. 10-6=4

Double check:
Mean: 10 + 8 + 6= 24/3= 8✔️
Median: 10,8,6= 8✔️
Range: 10,8,6. 10-6=4✔️
Numbers: 10,8,6

Answer 2

The 3 integers are 6 8 and 10

Explanation:

Comment

Start with the median. That's the middle number of an ordered set of numbers.

a 8 b is what you have so far.

Now the range between a and b is 4 which means that a and b differ by 4.

a + 4 = b

The mean will solve this quickly. Put a + 4 for b

[(a + 8 + a + 4)]/3 = 8 Combine like terms

(2a + 12)/3 = 8 Multiply both sides by 3

3 (2a + 12)/3 = 8 *3

2a+12 = 24 Subtract 12 from both sides

2a + 12 - 12 = 24-12 Combine

2a = 12

a = 6

but we know that the range between a (which is 6 ) and b is a + 4 = 10

So b must equal 10