Question

The length of a rectangle is 30ft more than the width. The perimeter of the rectangle is 128ft. Find the width and the length

Answer 1

The length is equal to 47ft

The width is equal to 17 ft

Explanation:

Perimeter = 2 × (length (l) ) + 2 × (width (w) )

We know that the perimeter is 128 ft and that the length is 30ft more then the width so you can substitute the length for 30 ft + w

Steps to solve

1. Apply what we know to the formula: The new equation is 2(w+30) + 2w = 128
2. Distribute 2 in 2(w+30) by multiplying each term in the parentheses: 2 × w is 2w and 2 × 30 is 60 so the new equation is 2w + 60 + 2w = 128
3. Combine like terms: The only like terms in the equation are 2w and 2w and 2w+ 2w is 4w. The new equation is 4w + 60 = 128
4. Subtact 60 on both sides: The point of subtracting 60 on both side is isolate w by itself. After doing so the new equation is 4w = 68
5. Divide 4 on both sides: Again we are getting w by itself ao we doing the inverse operations to do that. The width is 17 ft.
6. Apply the known variable 17 into the equation w + 30 to find the length. The length is 47 ft

*in case there was anything that confused you I have a attachment above tha showed the steps