Question

A bus is moving with the velocity of 60 km/h. By seeing a baby 11m ahead the driver applied the brakes and the re tardation produced is 13.88m/s². Calculate the distance covered by the bus and time taken to stop the bus.​

Answer 1

Answer: 12 seconds

Explanation:

u=60km/hr = (60×1000)÷(60×60)m/s = 50÷3 m/s

v=0 m/s

S=10m

We know: v^2 - u^2 =2as

a= -(u^2) ÷ (2s)

a= - (250÷9) ÷ (2×10) = - (25÷18) m/s^2

Now v=u +at

t = -(u)÷a = {-50÷(3)}÷{-25÷(18)}

Therefore, t= (50×18)÷(3×25) = 12 sec

I hope this helps :)