Question

I’m really stuck on this question and I can’t get the answer I’ve tried like 10 times can someone please help

Answer 1

S=1/2absinc

Solution:

16.27

Answer 2

16.27 mm² (2 d.p.)

Explanation:

Area of a triangle

`\boxed{ A=(1)/(2)ab \sin C}`

where:

• C is the angle.
• a and b are the sides enclosing the angle.

Given:

• a = 11 mm
• b = 14 mm
• C = θ = 12.2°

Substitute the given values into the formula and solve for A:

`\begin{aligned}A & = (1)/(2)ab \sin C\\\\\implies A & = (1)/(2)(11)(15) \sin (12.2^(\circ))\\& =82.5\sin (12.2^(\circ))\\& = 16.2720093...\\& = 16.27 \sf \;mm^2\; (2 \:d.p.)\end{aligned}`

Therefore, the area of the triangle is 16.27 mm² (2 d.p.).