Question

Triangle JKL is rotated 180° clockwise about the origin.

A four quadrant coordinate plane is
shown. Triangle J K L is graphed. Point J is
located at three comma six. Point K is
located at six comma two. Point L is
located at one comma two.

What are the coordinates of the vertices of J'K'L'?

A J'(−6, 3), K'(−2, 6), L'(−2, 1)
B J'(6, –3), K'(2, –6), L′(2, −1)
C J'(–3, –6), K'(-6, -2), L'(-1,-2) D J’(-3,6), K’(-6,2), L’(-1,2

Answer 1

we conclude that if JKL is rotated 180° clockwise about the origin, what are the new coordinates of point J(-4, 6) will be: J' (4, -6)

Hence, the answer choice (B) is correct.

Explanation:

The rule of rotating a point 180° clockwise about the origin states that if we rotate a point P(x, y) 180° clockwise about the origin, it would take a new position with the coordinates P'(-x, y).

In other words, the sign of its x and y coordinates change.

Thus, the rule is:

P(x, y) → P'(-x, -y)

Given the triangle ΔJKL with the coordinates

J(-4, 6)

K(-1, 2)

J(-4, 2)

Thus, according to the rule:

P(x, y) → P'(-x, -y)

The new position of point J (-4, 6) will be J' (4, -6)

The new position of point K (-1, 2) will be K' (1, -2)

The new position of point L (-4, 2) will be L' (4, -2)

Finally, we conclude that if JKL is rotated 180° clockwise about the origin, what are the new coordinates of point J(-4, 6) will be: J' (4, -6)

Hence, the answer choice (B) is correct.