Question

A particle P moves with constant velocity v. Initially P is at the point with position vector a. t seconds later P is at the point with position vector b. Find v when:

a= 2i + 3j, b= 6i + 13j , t = 2

Answer 1

correct

Explanation:

So the acute angle between the vectors is 7.122° (3sf). Explanation: The angle θ between two vectors →A and →B is related to the modulus.