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1 vote
What is the equation of a line that passes through the point (2,−2) and is perpendicular to y=x/4−3 ?

User Crossman
by
7.8k points

1 Answer

7 votes

Answer: y = -4x + 6

Explanation:

supposing m1 is the gradient of the line for whose equation we want to find

m1 * m2 =-1 for perpendicular lines

if m1 = 1/4

meaning m2 = -4

m2= -4 at point (2,-2)

we can get value of constant c

y = mx =c

-2 = (-4)(2) +c

c = 6

substituting c and m2 in gen eqn of line : y =mx +c

y = -4x + 6

User Chris Mitchelmore
by
7.8k points

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