Explanation:
8z^3+z^2+3z-1/z-1 you can use long division to get 8z^2+(9z^2+3z-1)/(z-1). You can keep dividing this equation until you get 8z^2+9z+12+11/z-1.
By using synthetic division, you can divide it into
1 -1. 8 1 3 -1 (a.k.a their coefficients)
Then bring the 8 down three, 1 down two, and 3, down one. Take that and multiply the one by each, and put it down. 8, 1, and 2. Then, do that with -1, to get -1, -2, and 1. So, the answer is 8z^2+9z+12+11+z-1. But since it's division, and there are 4 terms on one side, and 2 terms on the other, you have to divide it so it's 8z^2+9z+12+11/z-1.
Hope this makes sense!