Question

3. The ratio of milk water in 55 liters of Adultered milk is 7:4. How much water must be added to make the mixture Ratio of 7:6? a)5 liters b)10 liters c)15 liters

Answer 1

The answer is B 10 L

Explanation:

let milk and water in the mixture be 7x and 4x equal 55L

`7x + 4x = 55 \\ 11x = 55 \\ x = 5`

`7(5) = 35l \: milk \\ 4(5) = 20l \: water`

let x Liters of water he added so that the ratio is 7:6

`(35l \: milk)/(20l \: water + x) = (7)/(6)`

cross multiply

`35l \: milk * 6 = (20l \: water + x)7 \\ 210l \: m= 140l \: w + 7x \\ 210l \: m - 140l \: w = 7x \\ 70l = 7x \\ (70)/(7) = (7x)/(7 ) \\ x = 10 l \: water`