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NEED HELP ASAP!!! will give brian list!

NEED HELP ASAP!!! will give brian list!-example-1
User Ylka
by
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1 Answer

6 votes

Answer:

a. 28/143

b. 40/143

Explanation:

For both parts, we assume that the teas are selected without replacement. So we start with 13 teas. After one is selected, we have 12 teas left, and then after one more is selected, we have 11 teas left.

a. If all three are sweet:


(8)/(13) * (7)/(12) * (6)/(11) = (28)/(143)

b. If exactly one is sweet:

First one sweet, next two unsweet:


(8)/(13) * (5)/(12) * (4)/(11) = (40)/(429)

First one unsweet, second one sweet,

third one unsweet:


\ (5)/(13) * (8)/(12) * (4)/(11) = (40)/(429)

First two unsweet, third one sweet:


(5)/(13) * (4)/(12) * (8)/(11) = (40)/(429)

Adding these probabilities, we have


(120)/(429) = (40)/(143)

User Eduardo Oliveros
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