Question

For each sequence,find the first 4 terms and the 10th terms
3n+4
4n-5

Answer 1

Below in bold.

Explanation:

3n + 4:

The common difference = 3,

First term = 3(1) + 4 = 7

First 4 terms

= 7, 10, 13, 16

10th term = 3(10) + 4 = 34.

4n - 5:

The common difference = 4,

First term = 4(1) - 5 = -1

First 4 terms

= -1, 3, 7, 11

10th term = 4(10) - 5 = 35.