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A boy pulls a wagon with a force of 20 N on a handle .50 meters long. The end is .25 meters higher the the end attached to the wagon. What is the magnitude of the horizontal component that acts to pull
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A boy pulls a wagon with a force of 20 N on a handle .50 meters long. The end is .25 meters higher the the end attached to the wagon. What is the magnitude of the horizontal component that acts to pull the wagon forward?

User Trevor Hutto
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3 votes
Divide .25m/.50m for a total of .50
This is sort of like cosθ=adj/hyp=.25/.50=.600

Cos^-1 for .50 and your angle is 60°.

After that do 20N·sin 60°
This is hyp· sin θ

Your answer being 17N
User NullPointerException
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