x=11
y=8
z=12
Explanation:
x=first side
y=second side
z=third side
1. x=3+y
2. z=2y-4
3.x+y+z=31
input 1 and 2 into 3
(3+y)+y+(2y-4)=31
4y=32
therefore x=11 and z=12
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