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Two factory plants are making TV panels. Yesterday, Plant A produced 4 times as many panels as Plant B. Three percent of the panels from Plant A and 2% of the panels from Plant B were defective. How many panels did Plant B produce, if the two plants together produced 980 defective panels?

User Jasmijn
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1 Answer

6 votes

Answer:

7000 panels.

Explanation:

Let x be the number of panels produced by Plant B.

Therefore:

  • 4x = number of panels produced by Plant A.
  • x = number of panels produced by Plant B.

Given information:

  • Defective panels from Plant A = 3%
  • Defective panels from Plant B = 2%
  • Total number of defective panels = 980

Create an equation with the given information and defined variables, remembering to write the percentages in their decimal form:


\implies 0.03(4x) + 0.02x = 980

To find the number of panels Plant B produced, solve the found equation for x:


\implies 0.03(4x) + 0.02x = 980


\implies 0.12x + 0.02x = 980


\implies 0.14x = 980


\implies (0.14x)/(0.14) = (980)/(0.14)


\implies x=7000

Therefore, Plant B produced 7000 panels.

User Clement T
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