Question

A store owner mixes 2 lb of candy that costs x dollars per pound with 3 lb of candy

that costs $1.50 per pound. She sells the mix for $2.50 per pound.
How much did the 3 lb of the second type of candy cost the owner?

Answer 1

The 3 lb of the second type of candy cost the owner $12.

Step-by-step explanation:

To find out how much the 3 lb of the second type of candy cost the owner, we can set up an equation based on the given information.

Let's assume the cost of the candy per pound is $x. So, the cost of the 2 lb of the first type of candy would be 2x dollars.

The total cost of the candy is equal to the cost per pound multiplied by the total weight. So, the cost of the 2 lb candy is 2x dollars and the cost of the 3 lb candy is 3 * $1.50 = $4.50.

Since the mix is sold for $2.50 per pound, we can set up an equation: 2x + 4.50 = 2.50 * (2 + 3)

Simplifying the equation, we get: 2x + 4.50 = 12.50.

Subtracting 4.50 from both sides of the equation, we get: 2x = 8.

Dividing both sides of the equation by 2, we get: x = 4.

Therefore, the candy per pound costs $4.

The second type of candy weighs 3 lb, so the cost of the 3 lb candy would be 3 * $4 = $12. Therefore, the 3 lb of the second type of candy cost the owner $12.