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42 votes
42 votes
Two skaters face one another and stand motionless, then push against each other on the ice. If one's mass is 55 kg and he moves to the left after the push at a velocity of 4.3 m/s, how fast was the other skater traveling after the push if her mass was 48 kg.​

User Luke Hutteman
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1 Answer

17 votes
17 votes

4.9 m/s to the right

Step-by-step explanation:

We are going to use the conservation law of linear momentum to find her velocity. Initially, they are motionless so their initial total momentum is zero. Let's assume that anything moving to the left has a negative velocity and anything moving to the right has a positive velocity. We can write the conservation law of momentum as


0 = M_mv_m + M_wv_w

where


M_m = mass of the man = 55 kg


v_m = velocity of the man = -4.3 m/s


M_m = mass of the woman = 48 kg


v_w = velocity of the woman


\Rightarrow 0 = (55\:\text{kg})(-4.3\:\text{m/s}) + (48\:\text{kg})v_w

Solving for
v_w,


v_w = \left(\frac{55\:\text{kg}}{48\:\text{kg}}\right)(4.3\:\text{m/s}) = 4.9\:\text{m/s}

going to the right.

User Tomas By
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3.1k points