Question

The perimeter of a rectangle is 52 cm. If its width is 2 cm more than one-third of its length, find the dimensions of rectangle.

(A) 12 cm x 4 cm (B) 18 cm x 8 cm (C) 15 cm x 9 cm

Answer 1

(B) 18cm x 8cm

Explanation:

Perimeter of a rectangle = 52 cm

2(length + width) = 52 ==> l + w = 26

Let x be the length

width = (x/3) + 2

x + (x/3) + 2 = 26

[(3x + x)/3] + 2 = 26

4x / 3 = 24

4x = 24 (3)

x = 6(3) ==> 18 cm

Width = (18/3) + 2

= 6 + 2 = 8 cm

So, the required dimension is 18 cm x 8 cm.

Answer 2

(B) 18 cm x 8 cm

Explanation:

let the length be x,

then the width is
`(1)/(3)`x + 2

2(
`(1)/(3)`x + 2 + x ) = 52

`(1)/(3)`x + 2 + x = 26

`(4)/(3) x` = 24

x = (24*3)/4

x = 18

then the length is 18 cm

and width is (1/3)*18 + 2 = 8

Therefore the dimensions are length:width = 18 cm : 8 cm