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The height of a thrown football, in feet after t seconds is given by h(t) =-16^2+48^t+6. How many seconds does it take for the balls to reach maximum height after it is thrown?
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The height of a thrown football, in feet after t seconds is given by h(t) =-16^2+48^t+6. How many seconds does it take for the balls to reach maximum height after it is thrown?

The height of a thrown football, in feet after t seconds is given by h(t) =-16^2+48^t-example-1
User Maxim Sloyko
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Answer:

I don't know rjdjdjjdjddjidis

User FrankyHollywood
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