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A= h(b+c) solve for b

User Duo
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2 Answers

5 votes


\displaystyle\\Answer:\ b=(A-hc)/(h)

Explanation:


\displaystyle\\A=h(b+c)\\A=hb+hc\\A-hc=hb+hc-hc\\A-hc=hb\\Divide\ both\ parts\ of\ the\ equation\ by\ h(h\\eq 0):\\(A-hc)/(h)=b\\ Hence,\\b=(A-hc)/(h)

User Ginda
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Answer:

A=h(b+c) solve for c

First, multiply h to b and c

A = hb + hc

Then, transfer hb to the other side and change its sign from positive to negative.

A – hb = hc

To get c, Divide both sides by h

(A – hb)/h = hc/h

(A - hb)/h = c OR c = (A – hb)/h

Example. Let us assume the following. A = 500 ; h= 10;b= 20; c= ?

c = (A – hb)/h

c = (500 – (10*20))/10

c = (500 – 200)/10

c = 300/10

c = 30

To check; use the original equation given.

A = h(b+c)

A = 10(20+30)

A = 200 + 300

A = 500. same as the figure given in the example.

User KyleWpppd
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