Question

(a³b¹²c²) × (a³c²) × (b³c¹) ⁰ =

12.4
O A. a¹5¹24
○ в. a³b¹¹c³
8
O c. a³b¹²4
OD. a¹4b¹5c9

Answer 1

Explanation:

• keep in mind that any number to the power 0 is equal to 1 therefore if you check carefully in the expression you will find that
  `(b^(5) c^(4) )^(0) =1`
• And you should be able to know and apply the rules of exponents
• but in this case the only one to be applied is :if you are to are multiplying powers of the same base add the exponents.
• 
  `=a^(3) *a^(5)* b^(12) *c^(2) *c^(2)\\\\= a^(3+5) *b^(12) *c^(2+2)\\ =a^(8)b^(12) c^(4)`
• OPTION C IS the correct answer