Question

A car sitting at rest begins

accelerating at 2.40 m/s² for
15.0 seconds. How far has the
car gone?
(Units = m)

Answer 1

Using the equation of motion, the car accelerates at 2.40 m/s² for 15 seconds and travels a distance of 270 meters.

Step-by-step explanation:

The student has asked how far a car that accelerates from rest at a rate of 2.40 m/s² for 15.0 seconds will travel. To find the distance the car has traveled, we will use the equation of motion: d = v_i × t + ½ × a × t², where d is the distance, v_i is the initial velocity, a is the acceleration, and t is the time.

For this problem:

• Initial velocity, v_i, is 0 m/s (since the car is at rest).
• Acceleration, a, is 2.40 m/s².
• Time, t, is 15.0 s.

Plugging these values into the equation, we get:

d = 0 × 15.0 + 0.5 × 2.40 × (15.0)²

d = 0 + 0.5 × 2.40 × 225

d = 0.5 × 540

d = 270 meters

The car has gone a distance of 270 meters.