Answer:
16
Explanation:
You want the middle of three consecutive even integers that have a sum of 48.
Consecutive even integers
We can let x represent the middle of the three integers. Then the other two are (x -2) and (x +2), and their sum is ...
(x -2) +x +(x +2) = 48
3x = 48 . . . . . simplify
x = 16 . . . . . . divide by 3
The middle integer of the three is 16.
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Additional comment
As we see here, the average of the three integers is their sum divided by their number: 48/3 = 16. The middle of an odd number of consecutive integers will be equal to their average value. Hence, the middle integer must be 16.