Question

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Answer 1

Explanation:

O

3x² - 11x - 4 = 0

a = 3 ; b = -11 , c = -4

`Sum \ of \ roots = (-b)/(a)=(-(-11))/(3)=(11)/(3)\\\\Product \ of \ roots =(c)/(a)=(-4)/(3)\\\\`

W

8x² + 12x = -1

8x² + 12x + 1 = 0

a = 8 ; b = 12 ; c = 1

`Sum \ of \ roots =(-b)/(a)=(-12)/(8)=(-3)/(2)\\\\Product \ of \ roots = (c)/(a)=(1)/(8)`

L

x² + x = 6

x² + x - 6 = 0

a = 1 ; b= 1 ; c = -6

`Sum \ of \ roots = (-1)/(1)=-1\\\\Product \ of \ roots = (-6)/(1)=-6`

G

x²- 2x - 2 =0

a = 1 ; b = -2 ; c = -2

`Sum \ of \ roots = (-(-2))/(1)=2\\\\Product \ of \ roots = (-2)/(1)=-2`

E

4x - 5 = -4x²

4x² + 4x - 5 = 0

a = 4 ; b = 4 ; c = -5

`Sum \ of \ roots = (-4)/(4)=-1\\\\Product \ of \ roots=(-5)/(4)`

B

12x² +x -6 = 0

a = 12 ; b = 1 ; c = -6

`Sum \ of \ roots =(-1)/(12)\\\\Product \ of \ roots =(-6)/(12)=(-1)/(2)`

R

2x² + 5x - 25 = 0

a = 2 ; b = 5 ; c = -25

`Sum \ of \ roots=(-5)/(2)\\\\Product \ of \ roots =(-25)/(2)`

A

6x² -5x - 4 = 0

a = 6 ; b = -5 ; c = -4

`Sum \ of \ roots =(-[-5])/(6)=(5)/(6)\\\\Product \ of \ roots = (-4)/(6)=(-2)/(3)`