Answer: B.
Explanation:
First, we will solve both of these given inequalities for x by isolating the variables.
Given:
6 + 3y < 9
Subtract 6 from both sides of the equation:
3y < 3
Divide both sides of the equation by 3:
y < 1
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Given:
4y > 3y + 2
Subtract 3y from both sides of the equation:
y > 2
Now, our given inequalities are y < 1 and y > 2. These inequalities are easier to view on the graph. We see that these are not equal to (≥ or ≤), so we will have open circles.
First, we will graph y < 1. We will plot an open circle at y = 1 and then shade to the left of it. Net, we will graph y > 2. We will plot an open circle at y = 2 and then shade to the right of it. This leaves us with answer option B.