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A 13.2 KV circuit has a 10,000 kVA load with a 0.85 lagging power factor. How much capacitive reactive power (in KVAR) is needed to conect the P.F. to 0.97 lagging? ​
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A 13.2 KV circuit has a 10,000 kVA load with a 0.85 lagging power factor. How much capacitive reactive power (in KVAR) is needed to conect the P.F. to 0.97 lagging?

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A 13.2 KV circuit has a 10,000 kVA load with a 0.85 lagging power factor. How much-example-1
User Purple Tentacle
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Step-by-step explanation:

Solving for the capacitive reactive power, we have

Qc = 8,500 (tan(-cos (0.85)) - tan(-cos¹ (0.97)))

Qc = -3137.5261 = -3138 KVAR

A 13.2 KV circuit has a 10,000 kVA load with a 0.85 lagging power factor. How much-example-1
User Danywalls
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