Explanation:
since the process is defined by a constant term plus a variants term, the equation looks like
costs(c) = k + a×c
3,740,000 = k + 400a
7,000,000 = k + 1000a
let's simply subtract the guys from the second equation
7,000,000 = k + 1000a
- 3,740,000 = -k - 400a
------------------------------------
3,260,000 = 0 + 600a
600a = 3,260,000
a = 5,433.333333... 5,433 1/3
3,740,000 = k + 400×5,433.333333...
k = 3740000 - (400×5,433.333333...) =
= 1,566,666.66666...
so, the function is
costs(c) = 1,566,666.66666... + 5,433.333333... × c
therefore,
costs(2500) =
= 1,566,666.66666... + 5,433.333333... × 2500 =
= sh 15,150,000