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2.) A rectangular garden is 6 ft longer than it is wide. Its area is 352 ft2. What are its dimensions?

User Shtolik
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Answer:

Length = 22, Width = 16

Explanation:

Let L be the length of the garden and W the width

The area, A = L x W = 352 ft²

It is given that L = W + 6

Substituting for L in the area equation we get

L x W

==> (W + 6) x W = 352

Expanding the brackets

==> W.W + 6.W = 352

==> W² + 6W = 352

Subtract 352 from both sides:

W² + 6W - 352 = 0

This is a quadratic equation which can be solved using the quadratic formula.

- 352 = - 16 x 22 and -16 + 22 = 6

So we can factor the quadratic equation as
(W - 16) (W + 22) = 0

==> W = 16 or W = -22

Since we can disregard negative values in this context,

W = 16 and L = W + 6 = 16 + 6 = 22

Dimensions are Length = 22, Width = 16

User Suriya
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