Question

A cone-shaped tent has a diameter of 12 ft and a height of 6 ft. What is the approximate volume of the tent? Use 3. 14 to approximate pi, and express your final answer as a decimal. Enter your answer as a decimal in the box. Ft³.

Answer 1

226.08 ft³

Explanation:

`\textsf{volume of a cone}=(1)/(3)\pi r^2h`
(where
`r` = radius of the base and
`h` = height)

`\textsf{radius}\ r=(1)/(2)\ \textsf{diameter}`

Given:

• diameter = 12ft ⇒ radius = 12 ÷ 2 = 6 ft
• height = 6ft
• 
  `\pi` ≈ 3.14

`\implies \textsf{volume of tent}=(1)/(3)*3.14 * 6^2 * 6=226.08 \ \textsf{ft}^3`