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Find the remainder when 2x^10 - 3ix^8 + (1 + i)x^2 - (3 + 2i)x + 1 is divided by (x - i)

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User Brokedid
by
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1 Answer

1 vote

Use the polynomial remainder theorem. The remainder upon dividing a polynomial
p(x) by a linear factor
x-c is exactly
p(c).

In this case,


p(x) = 2x^(10) - 3ix^8 + (1+i)x^2 - (3+2i)x + 1

and
c=i. Then the remainder is


p(i) = 2i^(10) - 3i^9 + (1+i)i^2 - (3+2i)i + 1

Since
i^2=-1 and
i^4=1,


p(i) = -2 - 3i - 1 - i - 3i + 2 + 1 = \boxed{-7i}

User JamieL
by
3.1k points