Question

Differentiate the following equation
`sin^2((\pi )/(6) -x)`

Answer 1

`\sin^2\left((\pi )/(6)-x \right)\implies \left[ ~~ \sin\left((\pi )/(6)-x \right) ~~ \right]^2 \\\\\\ \stackrel{\textit{\LARGE Chain Rule}}{2\left[ ~~ \sin\left((\pi )/(6)-x \right) ~~ \right]^1 \left[ ~~ \cos\left((\pi )/(6)-x \right) ~~ \right] (-1)}\implies \boxed{-2\sin\left((\pi )/(6)-x \right)\cos\left((\pi )/(6)-x \right)}`