Question

What is the equation of the line that passes through the point (8,6)

and has a slope of frac{1}{4}

Answer 1

`(\stackrel{x_1}{8}~,~\stackrel{y_1}{6})\hspace{10em} \stackrel{slope}{m} ~=~ \cfrac{1}{4} \\\\\\ \begin{array}c \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{6}=\stackrel{m}{ \cfrac{1}{4}}(x-\stackrel{x_1}{8}) \\\\\\ y-6=\cfrac{1}{4}x-2\implies y=\cfrac{1}{4}x+4`