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Find the amount of money accumulated after investing a principle P for years t at interest rate r, compounded continuously. P = $10,000 r = 11% r = 11% t = 20 Round your answer to the nearest cent (hundredth). Enter

Find the amount of money accumulated after investing a principle P for years t at-example-1

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~~~~~~ \textit{Continuously Compounding Interest Earned Amount} \\\\ A=Pe^(rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$10000\\ r=rate\to 11\%\to (11)/(100)\dotfill &0.11\\ t=years\dotfill &20 \end{cases} \\\\\\ A=10000e^(0.11\cdot 20) \implies A=10000e^(2.2)\implies A \approx 90250.14

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