Question

Solve these problems please!!!

1. 4^5/4^2

2. 8^-2

3. 19a(2y)^3(y)^0 y=3
a=2

Answer 1

1. 64

2. 1/64

3. 8208

Explanation:

1.

4^5 = 1024

4^2 = 16

1024/16 = 64

2.

8^-2 = 8^(-1)x2

1/8^2 = 1/64

3.

19(2)x (2(3))^3(3)^0

38x6^3x1

38x216x1

=8208

Answer 2

Hope this helps!^^

Explanation:

1. 4^5/4^2

Apply exponent rule x^a/x^b=x^a-b

4^5-2

64

2. 8^-2

apply exponent rule a^-b =1/a^b

1/8^2

1/64

3. 19a(2y)^3(y)^0 y=3 a=2

First, lets complete the inside parenthesis

2*3=6

so
19a(6)^3(3)^0

19*2(6)^3(3)^0

8208