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If x=2 then solve |-3x - 5| + |-1 - x^2| + 2x^3

User Sydney
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1 Answer

4 votes

Answer:

32

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  • Work


\left|-3\left(2\right)-5\right|+\left|-1-2^2\right|+2\cdot \:2^3\\\left|-3\cdot \:2-5\right|+\left|-1-2^2\right|+2\cdot \:2^3\\-3 \cdot 2 - 5 = -11\\\left|-11\right|+\left|-1-2^2\right|+2\cdot \:2^3\\-1 - 2^2 = -1 - 4 = -5\\\left|-11\right|+\left|-5\right|+2\cdot \:2^3\\|-11| = 11\\|-5| = 5\\2 \cdot 2^3 = 2 \cdot 8 = 16\\11+5+16\\=32

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User Pankaj
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