Question

1.F(x)=x+25

f(37)

2.f(x)=-2x+20
F(20)

3.F(x)=-2x+20
F(-5)

4.f(x)=3x^2+4x+20
F(2)

5.f(x)= square root x-6
F(31)

6. square root x-8
F(4)

Answer 1

hope that this is helpful.

Explanation:

`1.f(x) = x + 25 \\ f(37) = 37 + 25 \\ = 62 \\ 2.f(x) = - 2x + 20 \\ f(20) = - 2(20) + 20 \\ = - 40 + 20 \\ = - 20 \\ 3.f(x) = - 2 x+ 20 \\ f( - 5) = - 2( - 5) + 20 \\ = 10 + 20 \\ = 30 \\ 4.f(x) = 3 {x}^(2) + 4x + 20 \\ f(2) = 3( {2}^(2) ) + 4(2) + 20 \\ = 3(4) + 8 + 20 \\ = 12 + 8 + 20 \\ = 40 \\ 5.f(x) = √(x - 6) \\ f(31) = √(31 - 6) \\ = √(25) \\ = 5 \\ 6. √(x - 8) \\ f(4) = √(4 - 8) \\ = √( - 4)`