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If 21,847 • 10^18 electrons pass through a wire in 12 s, find the current
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If 21,847 • 10^18 electrons pass through a wire in 12 s, find the current

User Nynohu
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Answer:

I = Q / t = N e / t

I = 21,847E18 * 1.60E-19 Coul / 12 sec = 2.18E22 * 1.60E-19 / 12 sec

I = 2.18 * 1.60 * 10^3 / 12 amps = 291 amps

User Omkar Guhilot
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