Question

A sample of Ne gas occupies 0.220L at 0.86 atm. What will be its volume at 29.4kPa?

Answer 1

0.66 L

Step-by-step explanation:

Here it's given that a sample of Neon occupies a volume of 0.220 L at 0.86 atm . And we need to find out its volume at 29.4 kPa .

If we assume temperature to be constant , then we can apply Boyle's Law , which states that ,

" For a fixed amount of gas at constant temperature , pressure is inversely proportional to the volume . "

Mathematically ,

`P \propto (1)/(V)`

Taking k as constant ,

`P =(k)/(V)`

And we can say that ,

`P_1 V_1 = P_2V_2`

Here ,

• P_1 = 0.87 atm
• P_2 = 29.4 kPa = 29400 Pa

As we know that ,

`0.987 atm = 10^5\ Pa`

So ,

`29400 Pa = 0.29 \ atm`

• V_1 = 0.220 L
• V_2 = ?

So that ,

`(0.87 atm )(0.220L) = (0.29atm)(V_2)\\`

`V_2 = (0.87 * 0.220)/(0.29) L`

Simplify ,

`V_2 = 0.66\ L`

Hence the new Volume of the gas is 0.66 L .

I hope this helps.