Question

Please help
write on paper or something
please
this is my finals

Answer 1

6.Ans;

`√(18) = √(9) √(2) = 3 √(2)`

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`- √(48) = - √(8) √(6) = - √(4) √(2) √(2) √(3) = - 2 √(4) √(3) = - 2 * 2 √(3) = - 4 √(3)`

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`√(75) = √(15) √(5) = √(5) √(3) √(5) = 5 √(3)`

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`\sqrt{ (30)/(49) } = ( √(30) )/( √(49) ) = ( √(5) √(6) )/( √(7) √(7) ) = ( √(5) √(6) )/(7) = ( √(30) )/(7)`

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`\sqrt{ (10)/(121) } = ( √(10) )/( √(121) ) = ( √(5) √(2) )/( √(11) √(11) ) = ( √(10) )/(11)`

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`\sqrt[3]{40} = \sqrt[3]{8} \sqrt[3]{5} = 2 \sqrt[3]{5}`

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`\sqrt[3]{54} = \sqrt[3]{27} \sqrt[3]{2} = 3 \sqrt[3]{2}`

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`- \sqrt[3]{128} = - \sqrt[3]{64} \sqrt[3]{2} = - 4 \sqrt[3]{2}`

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`\sqrt[3]{192} = \sqrt[3]{64} \sqrt[3]{3} = 4 \sqrt[3]{3}`

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`\sqrt[3]{ \frac{3m}{8 {n}^(3) } } = \frac{ \sqrt[3]{3m} }{ \sqrt[3]{8 {n}^(3) } } = \frac{ \sqrt[3]{3m} }{2n}`

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`\sqrt[3]{16 {a}^(5) } = \sqrt[3]{8 {a}^(3) } \sqrt[3]{2 {a}^(2) } = 2a \sqrt[3]{2 {a}^(2) }`

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`\sqrt[4]{80} = \sqrt[4]{16} \sqrt[4]{5} = 2 \sqrt[4]{5}`

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`\sqrt[4]{ (32)/(256) } = \frac{ \sqrt[4]{32} }{ \sqrt[4]{256} } = \frac{ \sqrt[4]{16} \sqrt[4]{2} }{ \sqrt[4]{16} \sqrt[4]{16} } = \frac{ \sqrt[4]{2} }{ \sqrt[4]{16} } = \frac{ \sqrt[3]{2} }{2}`

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`\sqrt[4]{ \frac{4 {x}^(2) }{81 {y}^(4) } } = \frac{ \sqrt[4]{4 {x}^(2) } }{ \sqrt[4]{81 {y}^(4) } } = ( √(2x) )/(3y)`

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`- \sqrt[5]{ (3)/(243) } = - \frac{ \sqrt[5]{3} }{ \sqrt[5]{243} } = - \frac{ \sqrt[5]{3} }{3}`

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`\sqrt[5]{ \frac{375}{32 {x}^(6) } } = \frac{ \sqrt[5]{375} }{ \sqrt[5]{32 {x}^(6) } } = \frac{ \sqrt[5]{375 {x}^(4) } }{2 {x}^(2) }`

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7.Ans ;

`\sqrt{36 {a}^(2) {b}^(3) } = 6ab √(b)`

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`\sqrt{27 {a}^(4) {b}^(3) } = 3 {a}^(2) b √(3b)`

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`\sqrt{72 {x}^(5) {y}^(2) } = 6 {x}^(2)y √(2x)`

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`- \sqrt{ {112}^(3) {b}^(4) } = - 448 {b}^(2) √(7)`

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`\sqrt{80 {m}^(4) {n}^(3) } = 4 {m}^(2)n √(5n)`

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`\sqrt{64 {x}^(2) {y}^(3) } = 8xy √(y)`

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`\sqrt[3]{16 {m}^(3) {n}^(3) } = 2mn \sqrt[3]{2}`

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`\sqrt[3]{ - 54 {x}^(4) {b}^(3) } = - 3xb \sqrt[3]{2x}`

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`- \sqrt[3]{128 {a}^(5) {y}^(3) } = - 4ay \sqrt[3]{2 {a}^(2) }`

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`\sqrt[3]{24 {p}^(3) {q}^(5) } = 2pq \sqrt[3]{3 {q}^(2) }`

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`\sqrt[4]{81 {x}^(4) {y}^(2) } = 3x √(y)`

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`- \sqrt[4]{256 {a}^(4) {b}^(5) } = - 4ab \sqrt[4]{b}`

I hope I helped you^_^

Answer 2

you can use this to attempt others