Question

The width of a rectangle is ten more than three times its length. If its perimeter is 108 meters, find the rectangle's dimensions.

Answer 1

Length be x

width be 3x+10

So

• 2(3x+10+x)=108
• 4x+10=54
• 4x=44
• x=11

width=3(10)+10=40m

Answer 2

Answer: the length is 3x+10

perimeter= 2 (width+length)

108=2(x+3x+10)

54=4x+10

4x=44

x=11(this is the width)

3x+10= 43(this is the length)

Explanation: