A spelunker explores a new underground cave. He descends into the cave at a rate of 4 feet per minute. What is the change in position of the spelunker after 50 minutes?

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Mistalis asked Apr 11, 2022

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A spelunker explores a new underground cave. He descends into the cave at a rate of 4 feet per minute. What is the change in position of the spelunker after 50 minutes?

Mathematics
high-school

Mistalis asked Apr 11, 2022

by Mistalis

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Answer:

4 * 50 = 200

Explanation:

Because he is descending at a rate of 4 feet every minute, after 50 minutes he is 200 feet down.

Lopata answered Apr 15, 2022

by Lopata

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