A spelunker explores a new underground cave. He descends into the cave at a rate of 4 feet per minute. What is the change in position of the spelunker after 50 minutes?

My account
Edit my Profile
Private messages
My favorites

Ask a Question
Questions
Tags
Categories
Ask a Question

Mistalis asked Apr 11, 2022

21,693 views

8 votes

A spelunker explores a new underground cave. He descends into the cave at a rate of 4 feet per minute. What is the change in position of the spelunker after 50 minutes?

Mathematics
high-school

Mistalis asked Apr 11, 2022

by Mistalis

3.0k points

0 Comments

Your comment on this question:

Email me at this address if a comment is added after mine:Email me if a comment is added after mine

Privacy: Your email address will only be used for sending these notifications.

Your answer

Email me at this address if my answer is selected or commented on:Email me if my answer is selected or commented on

Privacy: Your email address will only be used for sending these notifications.

1 Answer

16 votes

Answer:

4 * 50 = 200

Explanation:

Because he is descending at a rate of 4 feet every minute, after 50 minutes he is 200 feet down.

Lopata answered Apr 15, 2022

by Lopata

2.7k points

0 Comments

Your comment on this answer:

Email me at this address if a comment is added after mine:Email me if a comment is added after mine

Privacy: Your email address will only be used for sending these notifications.

Ask a Question

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

1.6m questions

2.0m answers

0 Comments

Your comment on this question:

Your answer

1 Answer

0 Comments

Your comment on this answer:

Other Questions