Question

(x+1)^2+(x-1)^2-2x(x+2)=0

Answer 1

x = 1/2

Explanation:

Step 1: Simplify both sides of the equation.

• 
  `(x+1)^2+(x-1)^2-2x(x+2)=0`
• 
  `x^2 + 2x + 1 + x^2 - 2x + 1 -2x^2 -4x = 0`
• 
  `(x^2 + x^2-2x^2) + (2x-2x-4x)+(1+1)=0`
• 
  `-4x + 2 = 0`

Step 2: Subtract 2 from both sides.

• 
  `-4x + 2 - 2 = 0 - 2`
• 
  `-4x = -2`

Step 3: Divide both sides by -4.

• 
  `(-4x)/(-4) = (-2)/(-4)`
• 
  `x = (1)/(2)`